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  1. How do you differentiate #f (x)= ln (sin (x^2)/x) - Socratic

    Dec 30, 2015 · To differentiate sin (x^2)/x, we'll need quotient rule. - Chain rule: (dy)/ (dx)= (dy)/ (du) (du)/ (dx) - Quotient rule: be y=f (x)/g (x), then y'= (f'g-fg')/g^2 We can rename u=sin (x^2)/x so that f …

  2. How do you implicitly differentiate 11= (x-y)/ (e^y-e^x)? | Socratic

    Multiply both sides of the equation by e^y - e^x Separate terms containing y to the left and x to the right. Differentiate each term.

  3. How do you differentiate the given function? F (y) = (#1/y^2 ... - Socratic

    Oct 10, 2017 · Your simplified equation should look at follows: F (y) = (y^-2 - 3y^-4) (y + 5y^3) STEP 2: In order to take the derivative for this problem, we will need to use the Product Rule. (in case you …

  4. How do you differentiate f (x)=sqrt ( (3x^2)/ (2x-3)) using ... - Socratic

    How do you differentiate f (x) = √ 3x2 2x − 3 using the chain rule? Calculus Basic Differentiation Rules Chain Rule

  5. How do you implicitly differentiate 15=x^2-y^2/x? | Socratic

    Mar 4, 2016 · See the explanation section, below. First of all, I would rewrite the equation. (Why use the quotient rule when we don't need to?) 15x=x^3-y^2 " " (for x != 0) Now differentiate: d/dx (15x)=d/dx …

  6. Question #33acf - Socratic

    (dy)/ (dx)=secxtanx-sec^2x To differentiate secx here'/ how it goes: secx=1/cosx You shall apply a quotient rule: that is "denominator (cosx)"xx"derivative of numerator" (1)-"derivative of denominator …

  7. Differentiate and simply and find the equation. Please read ... - Socratic

    Differentiate and simply and find the equation. Please read the image and help ?! Calculus

  8. How do you differentiate #g (x) = (2x^2 + 4x - 3) ( 5x^3 + 2x - Socratic

    (4x+4)(5x^3+2x+2)+(15x^2+2)(2x^2+4x-3) 50x^4+80x^3-33x^2+24x+2 First the product rule is, g(x)=fprime(x)h(x)+hprime(x)f(x) Where f(x)=2x^2+4x-3 And h(x)=5x^3+2x+2 Now take the derivative …

  9. If f (x)= tan8 x and g (x) = 2 x , how do you differentiate f (g (x ...

    Derivative of f (g (x)) is 32sec^2 16x. As f (x)=tan8x, (df)/ (dx)=sec^2 8x*8=16sec^2 8x and as g (x)=2x (dg)/ (dx)=2 and f (g (x))=tan8 (2x)=tan16x and according to ...

  10. How do you differentiate #f (x) = (1-5x)/ (2x^2+7)# using ... - Socratic

    Jan 11, 2016 · f' (x)= (10x^2-4x-35)/ ( (2x^2+7)^2 The quotient rule states that : d/dx [f (x)/g (x)]= (g (x)*f' (x)-f (x)*g' (x))/ ( [g (x)]^2). Application to this particular ...